
Fig. 4–3.Inclined plane. 倾斜的平面
The principle of the conservation of energyis very useful for deducing what will happen in a number of circumstances. Inhigh school we learned a lot of laws about pulleys and levers used in differentways. We can now see that these “laws” are all the same thing, and thatwe did not have to memorize 75 rules to figure it out. A simple example is a smooth inclined planewhich is, happily, a three-four-five triangle (Fig. 4–3). Wehang a one-pound weight on the inclined plane with a pulley, and on the otherside of the pulley, a weight W . We want to know how heavy W must be to balance the one pound on the plane. How can we figure thatout? If we say it is just balanced, it is reversible and so can move up anddown, and we can consider the following situation. In the initial circumstance,(a), the one pound weight is at the bottom and weight W is at the top. When W has slipped down in a reversible way, (b), we have a one-pound weightat the top and the weight W the slant distance, or five feet, from the plane in which it wasbefore. We lifted the one-pound weight only three feet and we loweredW pounds by five feet. Therefore W=3/5 of a pound. Note that we deduced this from the conservation ofenergy, and not from force components. Cleverness, however, is relative. Itcan be deduced in a way which is even more brilliant, discovered by Stevinusand inscribed on his tombstone. Figure 4–4explains that it has to be 35 of a pound, because the chain does not go around. It is evidentthat the lower part of the chain is balanced by itself, so that the pull of thefive weights on one side must balance the pull of three weights on the other,or whatever the ratio of the legs. You see, by looking at this diagram, that Wmust be 3/5 of a pound. (If you get an epitaph like that on your gravestone, youare doing fine.)

Fig. 4–4.The epitaph of Stevinus. 斯蒂维纽司的墓志铭
很多情况下,究竟会发生什么,都可以用能量守恒原理来解释。在高中,我们学了滑轮和杠杆在不同方式下使用的规律。现在我们可以看到,这些规律,都是同一个事情,这样,我们就没必要去记75条规则,以把它搞清楚了。一个简单的例子,就是一个光滑的斜面,它恰好是3、4、5三角形,见图4-3。我们在斜面上,用一个滑轮,吊着一磅重,在滑轮的另一面,是重量W。我们想知道,W应该有多重,才能平衡斜面上的那一磅。我们如何才能搞清楚呢?如果我们说,它刚好已经平衡了,那么,它就是可反转的,于是就可以来回移动,这样我们就可以考虑下面的情况。在初始情况下,(a),一磅重,在底部,重量W,在顶部。当W以一种可反转的方式,滑动到下面时,(b),一磅重,在顶部,而重量W,距其先前所在位置的距离,就是斜面的长度,或五英尺。我们把一磅重抬高了三英尺,把W降低了五英尺。因此W是1磅的3/5。注意,我们是从能量守恒,推出这点的,而不是从力的构成。然而,聪明是相对的。还有一种更加才华横溢的方法,可以推出它。该方法由斯蒂维纽司发现,且刻在他的墓碑上。图4-4解释了,确实应该是一磅的3/5,因为链子并不是转着圈走。很明显,下部的链子,是自平衡的,于是,在一侧拉这五个重量的,与另一侧拉三个重量的,应该平衡,且不论这个绳子的比例是多少。你看,通过看这个图,W应该是一磅的3/5。(如果你的墓碑上,有这么一个墓志铭,说明你很棒。)