感觉c指针骗了我，大佬过来喵喵，过来瞧瞧

完整代码如下
#include<stdio.h>
void testpp();
void main()
{
testpp();
}
//一级指针转二级指针
//无中间变量
void testpp()
{
long *a;
a=(long*)malloc(sizeof(long)*2);
*a=(long*)malloc(sizeof(long)*2);
*(a+1)=2;
*((long *)*a)=3;
*((long *)(*a+1))=4;
printf("*(a+1)=%d\n",*(a+1));
printf("*a=%d\n",*a);
printf("*((long *)(*a))=%d\n",*((long *)*a));
printf("*((long *)(*a+1))=%d\n",*((long *)(*a+1)));
free((long *)*a);
free(a);
}

我确实用的*来取地址的内容啊，我也用*赋值了啊，结果不一样，用的事Codeblocks+gcc

有毒啊，这是，

有人吗？

#include<stdio.h>
#include<stdlib.h>
//#define long int
void testpp();
void main()
{
testpp();
}
//一级指针转二级指针
//无中间变量
void testpp()
{
long *a,*tmp;
a=(long*)malloc(sizeof(long)*2);
*a=(long)malloc(sizeof(long)*6);
*(a+1)=2;
#if 0
*((long*)a[0]+1)=5;
printf("*((long*)a[0]+1)=%ld\n",*((long*)a[0]+1));
#endif
*((long *)*a+0)=1;
*((long *)*a+1)=2;
*((long *)*a+2)=4;
*((long *)*a+3)=8;
*((long *)*a+4)=12;
printf("*(a+1)=%ld\n",*(a+1));
printf("*((long*)*a+0)=%ld\n",*((long*)*a+0));
printf("*((long*)*a+1)=%ld\n",*((long*)*a+1));
printf("*((long*)*a+2)=%ld\n",*((long*)*a+2));
printf("*((long*)*a+3)=%ld\n",*((long*)*a+3));
printf("*((long*)*a+4)=%ld\n",*((long*)*a+4));
free((long *)*a);
free(a);
}
搞定，结帖掉了。