[0]{n}＝f_0(n)
[0]2{n}＝f_1(n)
[1]{n}＝f_ω(n)
[1]＋[0]{n}＝f_ω＋1(n)
[1]2{n}＝f_ω2(n)
[2]{n}＝f_ω^2(n)
[[1]]{n}＝f_ω^ω(n)
[[[1]]]{n}＝f_ω^ω^ω(n)
[(1,0)]{n}＝f_ψ(Ω)(n)

[(1,0)＋1]{n}＝f_ψ(Ω＋1)(n)
[(1,0)＋[(1,0)]]{n}＝f_ψ(Ω＋ψ(Ω))(n)
[(1,0)2]{n}＝f_ψ(Ω2)(n)
[(1,0)[(1,0)]]{n}＝f_ψ(Ωψ(Ω))(n)
[(1,0)^2]{n}＝f_ψ(Ω^2)(n)
[(1,0)^[(1,0)]]{n}＝f_ψ(Ω^ψ(Ω))(n)
[(1,0)^(1,0)]{n}＝f_ψ(Ω^Ω)(n)
[(1,0)^(1,0)＋[(1,0)^(1,0)]]{n}＝f_ψ(Ω^Ω＋ψ(Ω^Ω))(n)
[(1,0)^(1,0)＋(1,0)]{n}＝f_ψ(Ω^Ω＋Ω)(n)
[(1,0)^(1,0)＋(1,0)^2]{n}＝f_ψ(Ω^Ω＋Ω^2)(n)
[(1,0)^(1,0)·2]{n}＝f_ψ(Ω^Ω·2)(n)
[(1,0)^((1,0)＋1)]{n}＝f_ψ(Ω^(Ω＋1))(n)
[(1,0)^((1,0)^(1,0))]{n}＝f_ψ(Ω^(Ω^Ω))(n)
[(1,1)]{n}＝f_ψ(Ω_2)(n)

现在省略FGH
[(1,1)＋(1,0)]＝ψ(Ω_2＋Ω)
[(1,1)＋[(1,1)]_1]＝ψ(Ω_2＋ψ_1(Ω_2))
[(1,1)2]＝ψ(Ω_2·2)
[(1,1)[(1,1)]]＝ψ(Ω_2·ψ(Ω_2))
[(1,1)(1,0)]＝ψ(Ω_2·Ω)
[(1,1)[(1,1)]_1]＝ψ(Ω_2·ψ_1(Ω_2))
[(1,1)^2]＝ψ(Ω_2^2)
[(1,1)^(1,1)]＝ψ(Ω_2^Ω_2)
[(1,2)]＝ψ(Ω_3)
[(1,2)＋(1,0)]＝ψ(Ω_3＋Ω)
[(1,2)＋[(1,1)]_1]＝ψ(Ω_3＋ψ_1(Ω_2))
[(1,2)＋(1,1)]＝ψ(Ω_3＋Ω_2)
[(1,2)＋[(1,2)]_1]＝ψ(Ω_3＋ψ_2(Ω_3))
[(1,2)2]＝ψ(Ω_3·2)
[(1,2)^2]＝ψ(Ω_3^2)
[(1,2)^(1,2)]＝ψ(Ω_3^Ω_3)
[(1,3)]＝ψ(Ω_4)
[(1,[1])]＝ψ(Ω_ω)
[(1,[(1,[1])])]＝ψ(Ω_ψ(Ω_ω))
[(1,(1,0))]＝ψ(Ω_Ω)
[(1,(1,0)＋1)]＝ψ(Ω_(Ω＋1))
[(1,(1,0)2)]＝ψ(Ω_(Ω2))
[(1,(1,0)^2)]＝ψ(Ω_(Ω^2))
[(1,[(1,1)]_1)]＝ψ(Ω_ψ_1(Ω_2))
[(1,[(1,(1,0))]_1)]＝ψ(Ω_ψ_1(Ω_Ω))
[(1,[(1,(1,[(1,1)]_1))]_1)]＝ψ(Ω_ψ_1(Ω_ψ_1(Ω_2)))
[(1,(1,1))]＝ψ(Ω_Ω_2)
[(1,(1,(1,0)))]＝ψ(Ω_Ω_Ω)
[(1,(1,(1,[(1,(1,(1,0)))]_1)))]＝ψ(Ω_Ω_ψ_1(Ω_Ω_Ω))
[(1,(1,(1,1)))]＝ψ(Ω_Ω_Ω_2)
[(1,(1,(1,(1,0))))]＝ψ(Ω_Ω_Ω_Ω)
[(2,0)]＝ψ(I)

[(2,0)＋[(2,0)]_(2,0)]＝ψ(I＋ψ_I(I))
[(2,0)2]＝ψ(I·2)
[(2,1)]＝ψ(Ω_I＋1)
[(2,[(2,0)]_(2,0))]＝ψ(Ω_I＋ψ_I(I))
[(2,[(2,1)]_(2,0))]＝ψ(Ω_I＋ψ_I(Ω_I＋1))
[(2,(2,0))]＝ψ(Ω_I2)
[(2,(2,1))]＝ψ(Ω_Ω_I＋1)
[(3,0)]＝ψ(I_2)
[(3,0)＋(2,0)]＝ψ(I_2＋I)
[(3,0)＋[(3,0)]_(3,0)]＝ψ(I_2＋ψ_I_2(I_2))
[(3,0)2]＝ψ(I_2·2)
[(3,1)]＝ψ(Ω_(I_2)＋1)
[(3,(3,1))]＝ψ(Ω_Ω_(I_2)＋1)
[(4,0)]＝ψ(I_3)
[([1],0)]＝ψ(I_ω)
[((1,0),0)]＝ψ(I_Ω)
[((1,1),0)]＝ψ(I_Ω_2)
[((2,0),0)]＝ψ(I_I)
[(1,0,0)]＝ψ(I(1,0))

@增量游戏君 @古者

[(1,0,1)]＝ψ(Ω_I(1,0)＋1)
[(1,1,0)]＝ψ(I_I(1,0)＋1)
[(2,0,0)]＝ψ(I(1,1))
[(1,0,0,0)]＝ψ(I(2,0))
[(1,0,0,1)]＝ψ(Ω_I(2,0)＋1)
[(1,0,1,0)]＝ψ(I_I(2,0)＋1)
[(1,1,0,0)]＝ψ(I(1,I(2,0)＋1))
[(2,0,0,0)]＝ψ(I(2,1))
[(1,0,0,0,0)]＝ψ(I(3,0))
[(1@[1])]＝ψ(I(ω,0))
[(1@(1,0))]＝ψ(I(1,0,0))
[(2@(1,0))]＝ψ(I(1,0,1))
[(1@(1,1))]＝ψ(I(1,1,0))
[(1@(2,0))]＝ψ(I(2,0,0))
[(1@(1,0,0))]＝ψ(I(1,0,0,0))
[(1@(1@ω))]＝ψ(M^ω)
[(1;0)]＝[(1,0,0,0)]＝ψ(M)
[(1;0)^(1;0)]＝ψ(M^M)
[Ω_(1;0)＋1]＝ψ(Ω_M＋1)
[I_(1;0)＋1]＝ψ(I_M＋1)
[I(1,(1;0)＋1)]＝ψ(I(1,M＋1))
[I(1,0,(1;0)＋1)]＝ψ(I(1,0,M＋1))
[(1;1)]＝ψ(M_2)
[(1;(1,0))]＝ψ(M_Ω)
[(1;(1;0))]＝ψ(M_M)
[(2;0)]＝ψ(M(1,0))
[(2;1)]＝ψ(M_M(1,0)＋1)
[(3;0)]＝ψ(M(1,1))
[(1;0;0)]＝ψ(M(2,0))
[(1;0;1)]＝ψ(M_M(2,0)＋1)
[(1;1;0)]＝ψ(M(1,M(2,0)＋1))
[(2;0;0)]＝ψ(M(2,1))
[(1;0;0;0)]＝ψ(M(3,0))
[(1;@[1])]＝ψ(M(ω,0))
[(1;@(1;0))]＝ψ(M(M,0))
[(1;@(1,0))]＝ψ(M(1,0,0))
[(1;@(1;0;0))]＝ψ(M(1,0,0,0))
[(1;@(1;@[1]))]＝ψ(M(1@ω))＝ψ(M(1;0)^M(1;0)^ω)
[(1~0)]＝ψ(M(1;0))
[Ω_(1~0)＋1]＝ψ(Ω_M(1;0)＋1)
[M(1;0;(1~0)＋1)]＝ψ(M(1;0;M(1;0)＋1))
[(1~1)]＝ψ(M(1;1))
[(2~0)]＝ψ(M(2;0))
[(1~0~0)]＝ψ(M(1;0;0))
[(1~@[1])]＝ψ(M(1;@ω))
[(1~@(1,0))]＝ψ(M(1;@(1,0)))＝ψ(K)

继续下去随便上SSO

[(1;0)]＝[(1@(1,0))]＝ψ(I(1,0,0))＝ψ(M)
[(1;0)2]＝[(1@(2,0))]＝ψ(I(2,0,0))＝ψ(M2)
[(1;0)[(1;0)]_(1;0)]＝[(1@(1@(1,0),0))]＝ψ(I(I(1,0,0),0,0))＝ψ(Mψ_M(M))
[(1;0)^2]＝[(1@(1,0,0))]＝ψ(I(1,0,0,0))＝ψ(M^2)
[(1;0)^[1]]＝[(1@(1@ω))]＝ψ(I(1,0,…,0,0))＝ψ(M^ω)

令
,＝<1>
;＝<2>
~＝<3>
[(1<4>0)]＝ψ(K)
[(1<4>0)^ω]＝ψ(K^ω)＝ψ(M(1;@(1,0,…)))
[(1<4>0)^(1<4>0)]＝ψ(K^K)
[(1<4>1)]＝ψ(K_2)
[(2<4>0)]＝ψ(K(1,0))
然后我就不知道怎么套了

挑战成功了@古者 @增量游戏君
[0]＝1
[1]＝ω
[(A)]＝ψ(Ω)
[(A)2]＝ψ(Ω2)
[(A)^2]＝ψ(Ω^2)
[(A)^(A)]＝ψ(Ω^Ω)
[(A2)]＝ψ(Ω_2)
[(A2)＋[(A2)]_1]＝ψ(Ω_2＋ψ_1(Ω_2))
[(A[1])]＝ψ(Ω_ω)
[(A[(A)])]＝ψ(Ω_ψ(Ω))
[(A(A))]＝ψ(Ω_Ω)
[(A(A)＋A)]＝ψ(Ω_(Ω＋1))
[(A(A)＋A2)]＝ψ(Ω_(Ω＋2))
[(A(A)2)]＝ψ(Ω_(Ω2))
[(A(A)(A))]＝ψ(Ω_(Ω^2))
[(A(A)(A)＋A)]＝ψ(Ω_(Ω^2＋1))
[(A(A)(A)＋A(A))]＝ψ(Ω_(Ω^2＋Ω))
[(A(A)(A)＋A(A)＋A)]＝ψ(Ω_(Ω^2＋Ω＋1))
[(A(A)(A)＋A(A)2)]＝ψ(Ω_(Ω^2＋Ω2))
[(A(A)(A)2)]＝ψ(Ω_(Ω^2·2))
[(A(A)(A)(A))]＝ψ(Ω_(Ω^3))
[(A(A)^[1])]＝ψ(Ω_(Ω^ω))
[(A(A)^(A))]＝ψ(Ω_(Ω^Ω))
[(A[(A2)]_1)]＝ψ(Ω_ψ_1(Ω_2))
[(A(A2))]＝ψ(Ω_(Ω_2))
[(A^2)]＝ψ(I)
[(A^2＋A)]＝ψ(Ω_I＋1)
[(A^2＋A(A^2＋A))]＝ψ(Ω_Ω_I＋1)
[(A^2·2)]＝ψ(I_2)
[(A^2·(A))]＝ψ(I_Ω)
[(A^2·(A^2))]＝ψ(I_I)
[(A^3)]＝ψ(I(1,0))
[(A^3＋A)]＝ψ(Ω_I(1,0)＋1)
[(A^3＋A^2)]＝ψ(I_I(1,0)＋1)
[(A^3·2)]＝ψ(I(1,1))
[(A^3·(A^3))]＝ψ(I(1,I(1,0)))
[(A^4)]＝ψ(I(2,0))
[(A^[1])]＝ψ(I(ω,0))
[(A^(A))]＝ψ(I(Ω,0))
[(A^A)]＝ψ(I(1,0,0))＝ψ(M)
[(A^A＋A)]＝ψ(Ω_M＋1)
[(A^A＋A(A^A＋A))]＝ψ(Ω_Ω_M＋1)
[(A^A＋A^2)]＝ψ(I_M＋1)
[(A^A＋A^2＋A)]＝ψ(Ω_I_M＋1＋1)
[(A^A＋A^2·2)]＝ψ(I_M＋2)
[(A^A＋A^3)]＝ψ(I(1,M＋1))
[(A^A＋A^3＋A)]＝ψ(Ω_I(1,M＋1)＋1)
[(A^A＋A^3＋A^2)]＝ψ(I_I(1,M＋1)＋1)
[(A^A＋A^3·2)]＝ψ(I(1,M＋2))
[(A^A＋A^4)]＝ψ(I(2,M＋1))
[(A^A＋A^[1])]＝ψ(I(ω,M＋1))
[(A^A＋A^(A^A＋A))]＝ψ(I(Ω_M＋1,M＋1))
[(A^A·2)]＝ψ(M_2)
[(A^A·(A^A))]＝ψ(M_M)
[(A^(A＋1))]＝ψ(M(1,0))
[(A^(A＋1)＋A)]＝ψ(Ω_M(1,0)＋1)
[(A^(A＋1)＋A^2)]＝ψ(I_M(1,0)＋1)
[(A^(A＋1)＋A^A)]＝ψ(M_M(1,0)＋1)
[(A^(A＋1)·2)]＝ψ(M(1,1))
[(A^(A＋2))]＝ψ(M(2,0))
[(A^(A2))]＝ψ(M(1,0,0))＝ψ(M(1;0))
[(A^(A^2))]＝ψ(M(1;0;0))
[(A^(A^[1]))]＝ψ(M(1;@ω))
[(A^(A^(A^A)))]＝ψ(M(1;@M))
[(A^(A^A))]＝ψ(M(1;@(1,0)))＝ψ(K)
[(A^(A^(A^A)))]＝ψ(κ)
[(A_2)]＝ψ(Π_ω)

[(A(1;1))]＝ψ(λα.(Ω_α＋1)-Π_0)
[(A(1;[1]))]＝ψ(λα.(Ω_α＋ω)-Π_0)
[(A(1;A))]＝ψ(λα.(Ω_α2)-Π_0)
[(A(1;A(1;1)))]＝ψ(λα.(Ω_Ω_α＋1)-Π_0)
[(A(1;1,0))]＝ψ(λα.(ψ_I_α＋1(I_α＋1))-Π_0)
[(A(2;0))]＝ψ(λα.(I_α＋1)-Π_0)
[(A(2;1))]＝ψ(λα.(I(1,α＋1))-Π_0)
[(A(2;1,0))]＝ψ(λα.(M_α＋1)-Π_0)
[(A(3;0))]＝ψ(λα.(K_α＋1)-Π_0)
[(A([1];0))]＝ψ(2-π-Π_0)
[(A(1,0;0))]＝ψ(ω-π-Π_0)
[(A(1;0;0))]＝ψ((1,0)-π-Π_0)
接下来进入猜测
[(A(1;@[1]))]＝ψ(Σ[ω])
[(A(1;@(1;0)))]＝ψ(Σ[1,0])
[(A(1;@(1;0;0)))]＝TSSO
[(A(1;@(1;@[1])))]＝SHO
[(A(1;@(1;@(1;0))))]＝1,ω
[(A(1;@(1;@(1;@[1]))))]＝?????
极限PTO(ZFC＋I_114514－114514＋1919810－1919810＋114514－1919810＋1919810－114514)