求助大佬们，这题怎么做

∫(0->1) f(x) dx
=[xf(x)]|(0->1)-∫(0->1) xf'(x) dx
=0 -∫(0->1) xarctan(x^2) dx
=-(1/2)∫(0->1) arctan(x^2) dx^2
=-(1/2)[x^2.arctan(x^2)]|(0->1) +∫(0->1) x^3/(1+x^4) dx
=-π/8 + (1/4)[ln|1+x^4|]|(0->1)
=-π/8 + (1/4)ln2