这是一个flagt题
二进制如下
0000000001110010000000000
0000000000011110100000000
0000000001110001000000000
0000000010111100000000000
0000000010101010000000000
0000000001100010100000000
0000000010101010100000000
0000000001000001100000000
1100011101110110100011000
0001000010110010010010100
0100111101000011101110011
0011110100101011001001001
1000001001100001001101000
1111000111111011100101000
1011011111001101111110111
1000110110010010101101100
1000111100111111111110111
0000000010110001100010100
0000000010010100101010001
0000000010101010100011001
0000000000100111111110010
0000000000011001011110111
0000000001001100100100001
0000000011000011011011001
0000000011010000101110101
python代码如下
from PIL import Image
with open("1和0的故事.txt", "r") as f:
data = [list(i.strip()) for i in f.readlines()]
# 7*7的定位标志
flag = [
[1, 1, 1, 1, 1, 1, 1],
[1, 0, 0, 0, 0, 0, 1],
[1, 0, 1, 1, 1, 0, 1],
[1, 0, 1, 1, 1, 0, 1],
[1, 0, 1, 1, 1, 0, 1],
[1, 0, 0, 0, 0, 0, 1],
[1, 1, 1, 1, 1, 1, 1]
]
img = Image.new("1", (25, 25))
for i in range(len(data)):
for j in range(len(data[1])):
# 左上角定位标志
if i < 7 and j < 7:
img.putpixel((i, j), flag[i][j] ^ 1)
# 左下角定位标志
elif i > 17 and j < 7:
img.putpixel((i, j), flag[i-18][j] ^ 1)
# 右上角定位标志
elif i < 7 and j > 17:
img.putpixel((i, j), flag[i][j-18] ^ 1)
else:
img.putpixel((i, j), int(data[i][j]) ^ 1)
img.resize((500, 500)).show()
请用go解决