python跳过中间程序，直接运行后面的程序

print("欢迎来到奶茶一条街^_^")
products =[["茶百道", "17"], ["coco", "18"], ["星巴克", "30"], ["瑞幸", "20"], ["一点点", "15"]]
i = 0
for info in products:
print(str(i)+"\t", products[i][0]+"\t", products[i][1], end="\n")
i += 1
# 定义一个购物车
shoopcar = []
# 定义清单名称列表
resinfo = []
count = 1
find_index = 0
strinfo = input("请输入你需要的奶茶编号(确定请按Q):")
if int(strinfo)>4:
print("输入的编号不存在！")
exit()
while str(strinfo) != "Q":
# 查找该物品在大的购物车是否存在过
strfind = products[int(strinfo)][0]
name_1 = []
if strfind in resinfo:
for info in shoopcar:
str_1 = shoopcar[find_index][0] # 商品名称
str_2 = shoopcar[find_index][1] # 商品价格
str_3 = shoopcar[find_index][2] # 商品数量
if strfind == str_1:
del shoopcar[find_index]
name_1.append(str_1)
name_1.append(str_2)
name_1.append(int(str_3)+1)
shoopcar.append(name_1)
find_index += 1
else:
# 定义一个每次选择的物品临时存放点
newcar = []
newcar.append(products[int(strinfo)][0])
newcar.append(products[int(strinfo)][1])
newcar.append(count)
resinfo.append(products[int(strinfo)][0])
shoopcar.append(newcar)
print(products[int(strinfo)][0]+"添加成功")
strinfo = input("请继续输入你需要的奶茶编号(确定请按Q):")
print(end="\n")
print("---------奥拉蛋奶茶购物车------")
# 结算商品的数量
resinfo = {}
print("编号" + "\t", "商品名称" + "\t", "商品价格" + "\t", "商品数量" + "\t", end="\n")
print("*"*20)
sum = 0
for i, info in enumerate(shoopcar):
print(str(i)+"\t", shoopcar[i][0]+"\t", shoopcar[i][1]+"\t", str(shoopcar[i][2])+"\t", end="\n")
sum += int(shoopcar[i][1]) * int(shoopcar[i][2])
print("小计："+str(sum)+"元")