回复：求SK+1题，有没有好心的大佬，能否发些SK+1题来吧里

刚才学习SK的时候看到作者有计算器,就算了下,把结果copy过来,希望能帮到大家.

Almost (+1) SK loop detected : (35=24)r4c12 - (24=56)r56c3 - (56=17)r89c3 - (17=36)r7c12 - (36=124)r7c46 - (124=36)r89c5 - (36=17)r56c5 - (17=35)r4c46 - loop
No contradiction when 5 at r4c7 is true and others are all false
Eliminations : r4c7 <> 3, r7c7 <> 3, r7c9 <> 3, r1c3 <> 5, r1c3 <> 6, r2c3 <> 6, r1c5 <> 6, r2c5 <> 3, r2c5 <> 6, r5c4 <> 1, r6c6 <> 7, r8c1 <> 7, r9c2 <> 1, r8c4 <> 1, r8c6 <> 4

G46(124)，HI(124)三个数字两格，可以传递？

八宫多了一个候选数，要修正吧。

@风云际会JY😁 @💫小舟从此逝💫 来看看 ，这种候选没问题，直观37宫各多了一个明数，该怎么解决？

删数效果图。

@风云际会JY😁 @💫小舟从此逝💫 @忧来无方

我还没学直观网

20格网，定义域青色。删数域橙，绿色。没错呀。

直观网，橙格剩1226四个数字。

@💫小舟从此逝💫 照你刚才那个思路理解，算起来这个已经修成零网了22/22

复制一个帖子过来 还是2楼的题.

MS-AHS r1257c5689 (16 Cells)
(56)r1,(59)r2,(578)r5,(78)r7,(12)c5,(34)c6,(34)c8,(12)c9 (17 Digit Covers)
Potential Eliminations 5r1c3, 5r1c7, 5r2c2, 9r2c4, 34r3c8, 12r3c9, 1r4c9, 578r5c1,
58r5c3, 8r5c4, 2r6c5, 3r6c8, 78r7c1, 8r7c3 (20 Candidates in 14 cells)
Here there are 17 digits occupying the 16 cells so one of them must be true in an external cell.
Now it can be noted the full set of PEs would leave box 1 without a 5 so identifying that it should be removed
from the Away set for either row 1 or row 2, but which row it should be isn't known.
There are now two ways to handle this
1) Add a Home set for box 1. This will fully cover the candidates in the unsolved cells in the box and so
create a Naked Set of 21 cells with 21 digits.
2) Remove 5 from the covers for r1 and r2 and substitute them with a 5b3 cover (a 5b2 isn't needed as it is a
given in that box). This now reduces the digit covers to 16 to balance with the size of the Naked Set.
Note these changes have no effect on other PEs shown except of course they are now all validated.