求问大神这题具体步骤

i1=i2+i3
i1=(3+j4)A =5∠53.13° ,
i2=(x∠φ)A=xcos(φ)+jxsin(φ) ,
i3=(4∠60°)A=4cos(60°)+j4sin(60°)=2+j2√3 , f=50 Hz ，ω=2πf=314
KCL 求i2
i1=i2+i3
3+j4=[xcos(φ)+2]+j[xsin(φ)+2√3] ,得
xcos(φ)=1；xsin(φ)=4 -2√3 ,得 φ=atan(4 -2√3)=28.19° , x=1.1345
i2=1.1345∠28.19°
复数相量有效值转换瞬时值(振幅为有效值的√2倍)
i1=5∠53.13° , 瞬时值 i1(t)=7.07 cos(314t+53.13°)
i2=1.1345∠28.19° , 瞬时值 i2(t)=1.6 cos(314t+28.19°)
i3=4∠60° , 瞬时值 i3(t)=5.66 cos(314t+60°)