于是，我又回来了
既然没法同一种格式显示数字和字符两种类型，那就统一成字符好了（虽然我用的方法貌似很笨）
不多说了，上代码
/*做一个五子棋程序*/
#include <stdio.h>
int main(void)
{
int player = 0;
int winner = 0;
int row = 0;
int column = 0;
int line = 0;
char board [5][5] = {/*标记每个格子的位置*/
{' ',' ',' ',' ',' '},
{' ',' ',' ',' ',' '},
{' ',' ',' ',' ',' '},
{' ',' ',' ',' ',' '},
{' ',' ',' ',' ',' '}
};
for(int i = 0 ; i <= 25 && winner == 0;i++)
{/*绘制格子*/
printf(" 1 2 3 4 5 \n");
printf(" +----+----+----+----+----+\n");
printf("1 | %2c | %2c | %2c | %2c | %2c |\n",board[0][0],board[0][1],board[0][2],board[0][3],board[0][4]);
printf(" |----+----+----+----+----|\n");
printf("2 | %2c | %2c | %2c | %2c | %2c |\n",board[1][0],board[1][1],board[1][2],board[1][3],board[1][4]);
printf(" |----+----+----+----+----|\n");
printf("3 | %2c | %2c | %2c | %2c | %2c |\n",board[2][0],board[2][1],board[2][2],board[2][3],board[2][4]);
printf(" |----+----+----+----+----|\n");
printf("4 | %2c | %2c | %2c | %2c | %2c |\n",board[3][0],board[3][1],board[3][2],board[3][3],board[3][4]);
printf(" |----+----+----+----+----|\n");
printf("5 | %2c | %2c | %2c | %2c | %2c |\n",board[4][0],board[4][1],board[4][2],board[4][3],board[4][4]);
printf(" +----+----+----+----+----+\n");
/*玩家更替*/
player = i%2+1;
do
{/*提示玩家选择格子*/
printf("Player %d,please enter the number to place your %c in the board\n",player,(player == 1)?'O':'X');
scanf("%d %d",&row,&column);
}while(row<1 || column<1 || row>5 || column>5 || board[column-1][row-1] == 'O' || board[column-1][row-1] == 'X');/*判断格子选择正误*/
board[column-1][row-1]=(player == 1)?'O':'X';/*填入'X','O'*/
/*判断获胜条件是否达成*/
if( board[0][0] != ' ' && board[0][0] == board[1][1] && board[0][0] == board[2][2]
&& board[0][0] == board[3][3] && board[0][0] == board[4][4]
|| board[0][4] != ' ' && board[0][4] == board[1][3] && board[0][4] == board[2][2]
&& board[0][4] == board[3][1] && board[0][4] == board[4][0])
winner=player;
else
{
for(line = 0;line < 5;line++)
if(board[line][0] != ' ' && board[line][0] == board[line][1] && board[line][0] == board[line][2]
&& board[line][0] == board[line][3] && board[line][0] == board[line][4]
|| board[0][line] != ' ' && board[0][line] == board[1][line] && board[0][line] == board[2][line] && board[0][line] == board[3][line] && board[0][line] == board[4][line])
winner = player;
}
}/*和for配对的大括号*/
if(winner == 0)
printf("How pity！A draw game.");
else
printf("Congratulations!Player %d,you win the game!\n",player);
return 0;
}
输出结果（个人感觉目前最大的缺陷是有人胜利的话最后一步棋显示不出来...）

P.S.
顺便用字符数组将数字当成字符输出似乎是可以的...我也是看着教材上是这么写的才仿写下来了，毕竟照着打感觉不会有什么进步，楼下是图