我写了一个sql语句
$questionSql = "SELECT distinct `question` FROM `dis_relationship` WHERE `first_dis` LIKE '$site_id' and `relationshiptype`=$relationshiptype and `second_dis`='$second_dis'";
但是在这里报错：Notice: Array to string conversion in F:\A.I.Lab\xampp\htdocs\beijing\API\differentialDiagnosisOneVsOne.php on line 103
求解
$questionSql = "SELECT distinct `question` FROM `dis_relationship` WHERE `first_dis` LIKE '$site_id' and `relationshiptype`=$relationshiptype and `second_dis`='$second_dis'";
但是在这里报错：Notice: Array to string conversion in F:\A.I.Lab\xampp\htdocs\beijing\API\differentialDiagnosisOneVsOne.php on line 103
求解
