本人的代码为
public class Activity01 extends Activity {
Button button1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button button1 =(Button)findViewById(R.id.button1);
button1.setText("Begin");
button1.setOnClickListener(new Button.OnClickListener(){
public void onClick(View v)
{
Intent intent=new Intent();
intent.setClass(Activity01.this,Activity02.class);
startActivity(intent);
Activity01.this.finish();}});}
同理Activity02与上述相似,但为何运行时设置的两个button会出现在同一个界面,而且按了这两个按钮也不会切换,谢谢大家!
public class Activity01 extends Activity {
Button button1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button button1 =(Button)findViewById(R.id.button1);
button1.setText("Begin");
button1.setOnClickListener(new Button.OnClickListener(){
public void onClick(View v)
{
Intent intent=new Intent();
intent.setClass(Activity01.this,Activity02.class);
startActivity(intent);
Activity01.this.finish();}});}
同理Activity02与上述相似,但为何运行时设置的两个button会出现在同一个界面,而且按了这两个按钮也不会切换,谢谢大家!
