在dreamweaver cs6中写的连接到数据库代码如下:
<?php
$server="127.0.0.1";
$username="root";
$password="123456";
$database="zichao";
$conn=mysqli_connect($server,$username,$password)
or die("could not connect mysql");
mysql_select_db($database,$conn)
or die("could not open database");
?>
然后网页预览显示如下:
Warning: mysql_select_db() expects parameter 2 to be resource, object given in D:\server\Apache24\htdocs\config.php on line 8
could not open database
大神们帮帮我!!!
<?php
$server="127.0.0.1";
$username="root";
$password="123456";
$database="zichao";
$conn=mysqli_connect($server,$username,$password)
or die("could not connect mysql");
mysql_select_db($database,$conn)
or die("could not open database");
?>
然后网页预览显示如下:
Warning: mysql_select_db() expects parameter 2 to be resource, object given in D:\server\Apache24\htdocs\config.php on line 8
could not open database
大神们帮帮我!!!



