求助！！！！！关于数据定义问题

这是代码：
#include <iostream>
using namespace std;
class w{
int we;
public:
int address(){
we=1;int *q;
while(we<=10){cout<<q<<endl;q++;we++;}return 0;}};
int main(){
cout<<"1 world address of all"<<endl<<"2 address of fight"<<endl<<"3 address of all human"<<endl<<"4 exit"<<endl;
int i=1;while(i>=0){
int a;cin>>a;
if(a==1) {w b;b.address();}
if(a==2) {w b;b.address();}
if(a==3) {w b;b.address();}
if(a==4) break;}
return 0;}

自挽

你不是触发了断点，而是程序抛出了异常，q作为一个成员变量，你没有给它初始化，它就不被初始化，它直向哪里都不知道，你还q++，访问内存，这样会读到不能读的内存，当然就会抛出异常了

#include <iostream>
using namespace std;
class w{
int we;int *q;
public:int
address(){
we=1;while(we<=10){cout<<q<<endl;q++;we++;}
return 0;}
};
int main(){
cout<<"1 world address of all"<<endl<<"2 address of fight"<<endl<<"3 address of all human"<<endl<<"4 exit"<<endl;
int i=1;while(i>=0){
int a;cin>>a;
if(a==1) {w b;b.address();}
if(a==2) {w b;b.address();}
if(a==3) {w b;b.address();}
if(a==4) break;}
return 0;}

定义q的时候应该用int* q=new int;然后再给q一个值。并且在address函数的return(0)前面加上delete q。为什么你的程序会出现两个线程呢？明明只有一个的啊

#include "stdafx.h"
#include <iostream>
#include <iomanip>
using namespace std;
class w{
public:
int we;
int address(){we=1;
int* q=new int;
q=&we;
long m=(long) q;
while(we<=10){
cout<<setiosflags(ios::uppercase)<<setiosflags(ios::showbase)<<hex<<m<<endl;
m++;
we++;
}
return 0;
}
~w(){}
};
int main(){
cout<<"1 world address of all"<<endl
<<"2 address of fight"<<endl
<<"3 address of all human"<<endl
<<"4 exit"<<endl;
int i=1;
while(i>=0){
int a;
cin>>a;
if(a==1) {w b;b.address();}
if(a==2) {w b;b.address();}
if(a==3) {w b;b.address();}
if(a==4) break;
}
return 0;
}I