回复：【关于……算符重载】其实应该不难……但是……但是……

//好吧，败给你了，回来上电脑。
#include <vector>
//sth. else...
template <typename T>
class Matrix
{
public:
//sth. else...
typedef std::vector::size_type index;
T& operator()(index x, index y)
{ return this->data[x][y]; }
//sth. else...
private:
std::vector<std::vector<T> > data;
//sth. else...
};

kanqilaihaonandeyangzi.

思路上面已经给了，为了思路清楚把元素类和数组类分开讲，实现时可以直接把元素类放进数组类中：
#include<iostream>
#include<vector>
using namespace std;
template <typename T> class Arr
{
public:
vector<vector<T>> DATA;
vector<T> operator[](const size_t index)
{return DATA[index];}
T operator()(const size_t x,const size_t y)
{ return DATA[x][y];}
};
// 测试类
int main()
{
vector<int> a,b;
a.push_back(1);a.push_back(2);
b.push_back(10);b.push_back(20);
Arr<int> arr;
arr.DATA.push_back(a);
arr.DATA.push_back(b);
cout<<arr[0][0]<<endl; // 测试重载运算符
cout<<arr(1,1)<<endl;
system("pause");
return 0;
}

return &array[n*cow];

妹子的口气

好了好了，楼主的问题解决了，再拜叩谢各位相助！
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哟哟哟，还有个事……
不如告诉你们原题吧！
看：
Write a class of 2D array
Array2,
And the output of the following code should be:
0,1,2,3,
4,5,6,7,
8,9,10,11,
next
0,1,2,3,
4,5,6,7,
8,9,10,11,
#include <iostream>
using namespace std;
int main()
{
Array2 a(3,4);
int i,j;
for( i = 0;i < 3; i ++ )
for( j = 0; j < 4; j ++ )
a[i][j] = i * 4 + j;
for( i = 0;i < 3; i ++ ) {
for( j = 0; j < 4; j ++ ) {
cout << a(i,j) << ",";
}
cout << endl;
}
cout << "next" << endl;
Array2 b;
b = a;
for( i = 0;i < 3; i ++ ) {
for( j = 0; j < 4; j ++ ) {
cout << b[i][j] << ",";
}
cout << endl;
}
return 0;
}

啊哈哈哈 闹事的来了 不许删帖~~~

array指针保存row个int指针,每个int指针保存col个int类型,
第一个[]当做成员函数,接受一个row,返回对应的int指针,
第二个[]当做友元,接受一个指针和一个col返回int类型。