模拟龟兔赛跑（很笨拙的代码）

/*模拟龟兔赛跑*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
char *guiHold = NULL;
char *tuHold = NULL;
void gui(char *);
void tu(char *);
main()
{
int i = 0, m = 0, n = time(NULL), k = 0, j;
char weiZhi[70]; //定义70步路线
for(j = 0; j <= 69; j++) //初始化路线
weiZhi[j] = ' ';
tuHold = guiHold = weiZhi; //起始位置
printf("BANG!!!!!\nAND THET'RE OFF!!!!!\n");
printf("0\nT\nH\n");
for(; guiHold <= (weiZhi + 69) && tuHold <= (weiZhi + 69); m = time(NULL) - n) {
//按“1秒”的速度输出
if(i == m) { //当k = 0时 i == m表示时间还没有跳到下一秒，因此k + 1 = 1 执行 if
//后面的代码，下一次如果i == m，k继续+ 1 = 2；执行else进入下一次//循环，直到i != m
k++;
if(k == 1) {
printf("%d\n", m + 1);
gui(weiZhi); //调用龟的运动函数
for(j = 0; j <= 70 -1; j++) //打印龟位置
printf("%c", weiZhi[j]);
for(j = 0; j <= 69; j++) //初始化数组
weiZhi[j] = ' ';
printf("\n");
tu(weiZhi); //调用兔的运动函数
for(j = 0; j <= 70 -1; j++) //打印兔位置
printf("%c", weiZhi[j]);
for(j = 0; j <= 69; j++) //初始化数组
weiZhi[j] = ' ';
printf("\n");
if(guiHold == tuHold) //龟兔在同一个地方相撞
printf("OUCH!!!\n");
}
else
continue;
}
else {
i = m;
k = 0;
}
}
if(guiHold >= tuHold)
printf("\nGUI WINS!!!YAY!!!\n");
else if(guiHold == tuHold)
printf("\nIt's a tie!\n");
else
printf("\nTU Wins. Yuch.\n");
}
void gui(char *guiYundong) //龟的运动函数
{
int i, move;
srand(time(NULL));
i = 1 + rand() % 10;
if(i <= 5) //50%概率向前走3步
move = 3;
else if(i >= 6 && i <= 7) //10%概率向后退6步
move = -6;
else
move = 1; //40%概率向前走1步
*guiHold = ' ';
if((guiHold + move) < guiYundong) { //判断是否退过起点
printf("G");
guiHold = guiYundong; //
}
else {
*(guiHold + move) = 'G';
guiHold += move;
}
}
void tu(char *tuYundong) //兔的运动函数
{
int i, move;
srand(time(NULL));
i = 1 + rand() % 10;
if(i <= 2) //20%概率不退不进
move = 0;
else if(i >= 3 && i <= 4) //20%概率向前走9步
move = 9;
else if(i >= 5 && i <= 7) //30%概率向前走1步
move = 1;
else if(i == 8) //10%概率向后退12步
move = -12;
else //20%概率向后退2步
move = -2;
*tuHold = ' ';
if(tuHold + move < tuYundong) { //判断是否退过起点
printf("T");
tuHold = tuYundong;
}
else {
*(tuHold + move) = 'T';
tuHold += move;
}
}