初等方法证明:S = 1+2+3+4+5+…… = -1/12
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1,设:a = 1-1+1-1+1-1+……
则:2a = 1,a = 1/2
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2,再设:b = 1-2+3-4+5-6+……
则:2b = 1-1+1-1+1-1+1-1 = a,b = a/2 = 1/4
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3,再设:S = 1+2+3+4+5+……
根据:b = 1-2+3-4+5-6+7……
则:S - b = 4+8+12+16+20+…… = 4(1+2+3+4+……) = 4S
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立即可得:
- b = 3S
S = - b/3 = - 1/12